PROBLEM #1

1. The unit of POWER can be expressed as W, kW, hp, etc. Their equivalent expressions are J/s, kJ/s, in which J is joule to represent work and 1 J=0.101972kgm (You may find unit conversion table at http://www.digitaldutch.com/unitconverter/). Now, by using such relations find out the following condition when a farm tractor pulls a farm equipment working on the field at 20m/min. Suppose the draft force is meaured as 200kgf. Find out the power of the tractor.
   (試利用上述的關係，計算下面的情況：設若一台曳引機(Tractor)拉引某一農具，其拉力測得200公斤，試計算此需要多少功率(動力、馬力或kW)才能該農具在一分鐘內拉動20m？)
   
2. A circuit with three resistors rated 1, 20,200 ohms in series is connected to a voltage source of 110V. Find the line current and power consumption.
   (有一電路，以1、20及200歐姆之電阻器相串聯，試計算當此電路兩端加於110V電源時，其流經之電流及所耗之功率。)
   
3. Calculate the area of a trangle with three sides in 650cm, 428cm, 282cm, repectively.
   (一個三角形三邊分別為650、428、282cm，試計算其面積為多少平方公分。)
   
4. A hog house was designed the way that heat dissipations from lighting & equipment 25,000BTU/hr, heat flux through wall & cellings 52,000BTU/hr , heat flux through aerations 84,300BTU/hr. Suppose each hog will dissipate 600BTU/hr, how many hogs this house can raise?
   (在一個規模的現代化豬舍中，其照明及設備操作所產生的熱量為25,000BTU；設經過牆壁及屋頂之流出之熱流量每小時為52,000BTU（英熱單位），利用風扇散熱的熱流量每小時為84,300BTU。然而飼養的豬隻中，每隻每小時產生600BTU之熱。試求此豬場要養多少隻豬才是合適的情況？)
   
5. The flow rate of a rectangular water gate can be calculated from the following formula: Q=3.33x[L-0.2H]^(3/2), in which L: width of gate in ft, H:water head in ft and Q: the flow rate in cu. ft./s. Find the flow rate Q if L=4 ft and the wate head is 0.9 ft.
   (一個矩形堰之流量率通常用下列公式計計：Q=3.33x[L-0.2H]^(3/2)，其中Q為流量（立方呎／秒）；L為堰開口寬度（呎）；H為堰口溢流水頭高度（呎）。若堰口寬度為4呎，堰口溢流水頭高度為0.9呎，問其流量每秒為多少立方呎？)

Due Date(截止日期)：12:00PM, September 28, 2006